Question

The square of hypotenuse of a right angled isosceles triangle is 512cm. find the altitude and base of right angled.​

Answer 1

Answer:

a

${a}^{2} = b^{2} \\ a {}^{2} + {a}^{2} = 512 \\ 2 {a}^{2} = 512 \\ {a}^{2} = 256 \\ a = 16$

Step-by-step explanation:

isosceles triangle so two sides r equal

Answer 2

The square of hypotenuse of a right angled isosceles triangle is 512cm. find the altitude and base of right angled.​

(note : since it's given that it is a isosceles triangle, we are taking base and altitude as 'x'cm. As in a isosceles triangle, 2 sides are equal)

GIVEN,

Hypotenuse = 512cm

base = x altitude/height = x

we know that,

(PYTHAGOREUS THEOREM)

(A)² + (B)² = (C)² = (hypotenuse)²

x²+x² = 512

2x² = 512

$x^{2} = \frac{512}{2}$

x² = 256

x = √256

x = 16

Hence, the base and altitude are 16cm each.

Hope it helps!

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