The square of hypotenuse of a right angled triangle is 80 cm and one side is half of the other. Find the length of two sides.
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h^2=b^2+p^2
let the longer side be ( p)x
the smaller side(b)=x/2
80= (x)^2+(x/2)^2
80=x^2+ x^2/4
80=(4x^2+x^2)/4
320=5x^2
320/5=x^2
(64)^1/2=x
x=8 cm
x/4=4 cm
hope it helps you....
let the longer side be ( p)x
the smaller side(b)=x/2
80= (x)^2+(x/2)^2
80=x^2+ x^2/4
80=(4x^2+x^2)/4
320=5x^2
320/5=x^2
(64)^1/2=x
x=8 cm
x/4=4 cm
hope it helps you....
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