Question

The square of hypotenuse of a right angles triangle is 80cm and one side is half the other. Find the length of the two sides

Answer 1

Let in △ABCx△ABCx be the length of ABAB and x2x2be the length of BCBC. Applying pythagoras theorem,

(AB)2+(BC)2=(AC)2(AB)2+(BC)2=(AC)2

It is given that (AC)2=80(AC)2=80

x2+(x2)2=80x2+(x2)2=80

x2+x24=80x2+x24=80

5x24=805x24=80

Multiplying both sides by 4545,

x2=80∗45=5∗16∗45=64x2=80∗45=5∗16∗45=64

x=64−−√=8x=64=8


hope this will help u :-))

Hence AB=8cmAB=8cm and BC=82=4cm