Math, asked by omchattani04, 2 months ago

the square of odd natural number is​

Answers

Answered by Anonymous
1

Answer:

Sum of Squares of First n Odd Numbers.

Sum of: Formula

Squares of first odd natural numbers Σ(2n-1)2 =[n(2n+1)(2n-1)]/3

Step-by-step explanation:

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Answered by Anonymous
0

Answer:-

Squares of odd numbers are odd, since (2n + 1)2 = 4(n2 + n) + 1. It follows that square roots of even square numbers are even, and square roots of odd square numbers are odd. As all even square numbers are divisible by 4, the even numbers of the form 4n + 2 are not square numbers.

It is basically the addition of squared numbers.

Sum of Squares of First n Odd Numbers.

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