the square of side 12 cm is cut on diagonal . Find the perimeter of one triangle so formed
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square side = 12cm
diagonal^2 = 12^2 + 12^2
diagonal^2 = 12^2(1+1)
diagonal =12sqrt2
sides of formed triangle would be 12 , 12 & 12sqrt2
perimeter of triangle would be sum of all sides
perimeter = 12 + 12 + 12sqrt2
= 12×(1+1 + sqrt2)
= 12×(2 + 1.414)
= 12× 3.414
= 40.968 cm
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