the square of side 12 cm is cut on the diagonal find the perimeter of triangle so formed
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Step-by-step explanation:
Diagonal of a square= a√2
= 12√2
Therefore perimeter of triangle= 12 +12 + 12√2
= 24 +12√2
= 12 ( 2 + √2) cm
therefore perimeter of triangle formed= 12 (2+√2)
cm
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