The square of side 12cm is cut out on its diagonal. find its perimeter of one triangle so formed .
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since side of square are equal so in a triangle perpendicular and base are equal but hypotenuse(digital)are different.
so, h^2=p^2+b^2
h^2=(12)^2+(12)^2
h^2=16.97
perimeter of one triangle=sum of all side
perimeter=12+12+16.97=40.97
so, h^2=p^2+b^2
h^2=(12)^2+(12)^2
h^2=16.97
perimeter of one triangle=sum of all side
perimeter=12+12+16.97=40.97
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