The square of sum of two consecutive natural numbers is 40 more than the sum of their squares. Find the two consecutive natural numbers.
pls tell with method.
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the consecutive numbers of 124568 is 698965
so if it is 40 more we need to write in 49 times again so 528492727492836939282839394929823883849392738394849292028384849284747575748100394884749329
answer is 78.23
please mark me as brainiest i need only one brainlest to go to next ranck
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