The square of the binomial (2x3- 3y3)
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(2x³-3x³)²
=(2x³)²+(3x³)²-2(2x³)(3x³)
Answer=0
=(2x³)²+(3x³)²-2(2x³)(3x³)
Answer=0
Answered by
0
Answer:
Step-by-step explanation:
Let,2x3 = 6x = a
And,3y3 = 9y = b
Then square of the above equation in the question will be,
(6x-9y)² = 36x²-108xy+81y²
[ (a-b)²=a²-2ab+b²]
÷ing equation with 3 =>
12x²-36xy+27y²
=4x²-12xy+9y²
So, the square of the above equation in the question will be,
4x²-12xy+9y²
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