Math, asked by jiya4976, 7 months ago

The square of the greater of two consecutive even no.s exceeds the square of the smaller by 36. find the no.s
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Answers

Answered by Anonymous

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2 Consecutive even square numbers.

Difference = 36.

Let the numbers be n , n + 2 ( even )

Their squares will be = n^2 , ( n + 2 )^2

☞ ( n + 2 )^2 = n^2 + 36

☞ n^2 + 4n + 4 = n^2 + 36 ( cancel n^2 and n^2 )

☞ 4n + 4 = 36

☞ 4n = 36 - 4

☞ 4n = 32

☞ n = 32 / 4

☞ n = 8.

so, Another number = ( n + 2 )

☞ ( 8 + 2 )

☞ 10.

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