Question

The square of the greater of two consecutive even number exceeds the square of the smaller by 36. find the number​

Answer 1

Step-by-step explanation:

The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 . Find the number.

let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8

Answer 2

Step-by-step explanation:

AnswEr :

⠀⠀⠀⠀⠀Square of the greater of two consecutive even numbers exceeds square of smaller number by 36. Let's consider that two consecutive numbers are 'x' & 'x +2'.

__________________________

$\boxed{\bf{\mid{\overline{\underline{\bigstar\: According\: to \: the \: Question :}}}}\mid}$

$:\implies\tt \Big( x + 2 \Big)^2 = 36 + x^2 \\\\\\:\implies\tt x^2 + 4 + 4x = 36 + x^2 \\\\\\:\implies\tt 4x + 4 = 36 \\\\\\:\implies\tt 4x = 36 - 4 \\\\\\:\implies\tt 4x = 32 \\\\\\:\implies\tt x = \dfrac{32}{4} \\\\\\:\implies\tt x = 8$

$\dag\:\underline{\textsf{Here we get value of x is \textbf{8}}}.$

$:\implies\tt \Big(x + 2 \Big) \\\\\\:\implies\tt 8 + 2 \\\\\\:\implies\tt 10$

$\therefore\:\underline{\textsf{Required Numbers are \textbf{8 \& 10}}}.$