Question

The square of the greater of two consecutive even numbers exceeds the square of the smaller number by 63 find these numbers

Answer 1

Answer:

Step-by-step explanation:

⇒ previous consecutive even numbers

→ x , x+2

→ x² + 36 = (x+2)²

→ x² + 36 = x² + 4 + 4x

→ x² and x² cut down

→ 4(x+1) = 36

→ x+1 = 9

→ x = 9-1 = 8

→ x = 8

→ x+2 = 8+2 = 10

→ x = 10

Answer 2

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$let \: no. \: be \: x \: and \: x + 1$

$there \: sq. \: are \: {x}^{2} \: and \: (x + 1 {)}^{2}$

$the \: diff. \: is \: 36$

$= > (x + 1 {)}^{2} - {x}^{2} = 36$

${x}^{2} + 2x + 1 - {x}^{2} = 36$

$\cancel{x}^{2} + 2x + 1 - \cancel {x}^{2} = 36$

$2x + 1 = 36$

$2x = 36 - 1 = 35$

$x = \cancel\frac{{35}}{2} = 17.5$

$so \: the \: no. \: are \: 17.5 \: and \: 18.5$