Question

The square of the greater of two consecutive even numbers exceeds the square of the smaller no. by 63. Find these numbers. ​

Answer 1

Answer:

1

Secondary SchoolMath 10 points

The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 . Find the number.

Ask for details Follow Report by Raunak683 18.07.2017

Answers

Róunak

Róunak

Let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8

Step-by-step explanation:

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Answer 2

$\huge {\boxed {\fcolorbox{pink}{red} {\purple{ur\:answer}}}}$

$let \: no. \: be \: x \: and \: x + 1$

$there \: sq. \: are \: {x}^{2} \: and \: (x + 1 {)}^{2}$

$the \: diff. \: is \: 63$

$= > (x + 1 {)}^{2} - {x}^{2} = 63$

${x}^{2} + 2x + 1 - {x}^{2} = 63$

$\cancel{x}^{2} + 2x + 1 - \cancel {x}^{2} = 64$

$2x + 1 = 63$

$2x = 63 - 1 = 62$

$x = \cancel\frac{{62}}{2} = 31$

$so, \: the \: no. \: are \: 31 \: and \: 32$