Question

The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 . Find the number.

Answer 1

let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

  (x+2+x)(x+2-x)=36

  (2x+2)(2)=36

  2x+2=18

  2x=16

  x=8

Answer 2

The numbers are 8 and 10.

Step-by-step explanation:

Given:

The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 .

To find:

Find the numbers

Solution:

Let the consecutive numbers be x, x + 2

$(x + 2)^2 = 36 + x^2$

$X^2 + 4 + 4x = 36 + x^2$

4x + 4 = 36

4x = 36 – 4  

x =$\frac{32}{4}$ = 8

The numbers are 8 and 10

To know more:

The square of the greater of two consecutive even numbers exceeds the square of the smaller no. by 63. Find these numbers.

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