Question

The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 . Find the number.

Answer 1

Let the two consecutive even numbers be x, x+2
As per the problem
(x+2)^2=36+x^2
x^2+4+4x=36+x^2
4x+4=36
4x=36-4
4x=32
x=32/4
x=8
x+2=8+2=10

Thereforethe two consecutive even numbers are 8,10

Answer 2

Answer:

8 and 10

Step-by-step explanation:

Let the two consecutive even numbers be x an x+2

Let us suppose x+2 is the greater number .

Now we are given that The square of the greater of two consecutive even numbers exceeds the square of the smaller by 36

$(x+2)^2=x^2+36$

$x^2+4x+4=x^2+36$

$4x+4=36$

$4x=36-4$

$4x=32$

$x=8$

So, x+2 =8+2=10

Thus the numbers are 8 and 10