the square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 find the numbers
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let the nos be x and (x+2) becuz they are consecutive even nos .
let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36
let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36
let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36
let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36 2x+2=18
let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36 2x+2=18 2x=16
x= 8
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your answer is 8.......
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