Math, asked by iqbalhusain46513, 9 months ago

the square of the greater of two consecutive even numbers exceeds the square of the smaller by 36 find the numbers​

Answers

Answered by udbhavjha0
3

ANSWER :

let the nos be x and (x+2) becuz they are consecutive even nos .

let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36

let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36

let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36

let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36 2x+2=18

let the nos be x and (x+2) becuz they are consecutive even nos .so:(x+2)2 -x2 =36 (x+2+x)(x+2-x)=36 (2x+2)(2)=36 2x+2=18 2x=16

x= 8

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Answered by samanpreetchahal1234
0

Answer:

your answer is 8.......

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