Question

The square of the greater of two consecutive numbers exceeds the square of the smaller by 23. find the number

Answer 1

Answer:

The numbers are 11 and 12

Step-by-step explanation:

Let the smaller number be x ,then greater number will be (x+1) .

A/c to question, the difference between their square is 23 .

so, (x+1)²-(x)²= 23

=> x²+1+2x-x²= 23

=> 2x= 23-1=22

=> x= 11

so number are 11 and 12

Answer 2

Step-by-step explanation:

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