Question

the square of two positive integers differ by 4040 .Find their maximum possible sum​

Answer 1

Answer:

bigger number = x = 10

smaller number = y = 6

Step-by-step explanation:

bigger number = x

smaller number = y

x2 + y2 = 136

x -y =4

x = y+4

(y+4)2 + y2 = 136

y2 + 8y +16 +y2 = 136

2y2 + 8y - 120 = 0

y2 +4y - 60 =0

(y+10)(y-6)=0

y=-10 and y =6

we need positive number

so y = 6

x = y+4=6+4 =10

bigger number = x = 10

smaller number = y = 6