The square of two positive integers is differs by 2019. What is the sum of these two integers
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Answer:673
Step-by-step explanation:
Let's say the to integers are 'a' and 'b'.
Then, a^2-b^2=2019.
So, (a+b)(a-b)=2019.
As we can know that 2019=3*673 and a+b is bigger than a-b,
we can find out that a+b=673,a-b=3 (because a,b is positive integers).
So,a+b=673 (a=338,b=335)
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The answer for this question is 673
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