The square pf resultant of two equal forces is three times their scaler product. Angle between the forces is :
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Let the forces be a and b.
Given that, R=3A^2
now,
R^2=A^2+B^2+2ABcostheta
=>2A^2+2A^2 costheta
pitting the value R=3A^2
so,
3A^2=2A^2+2A^2costheta
solving this,
theta= 60 degree.
HAPPY TO HELP
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