Question

The square root of : (0.75)3/1-0.75+[0.75+(0.75)2+1] is:

Answer 1

Answer:

The square root of (0.75)3/1-(0.75) + (0.75+(0.75)2+1) is 2.

Explanation:

let, 0.75 =a

so, (0.75)^3 / (1-0.75) = a^3 / (1-a)

and, [0.75 + (0.75)^2 +1] = a+a^2+1= (a^2+a+1)(1-a) / (1-a)

= (a^2-a^3+a-a^2+1-a) /(1-a)

=(1-a^3) /(1-a)

now,

(0.75)^3 /(1- 0.75) +[ 0.75 +(0.75)^2 +1 ]

= a^3 /(1-a) + (1-a^3)/(1-a)

= (a^3+1-a^3) / (1-a)

= 1 / (1-a)

=1 /(1- 0.75) [putting, a= 0.75 ]

= 1 / 0.25

=1 / (25/100)

=1 / (1/4)

= 4 =2^2

sq.rt = 2

Answer 2

dude the answer is 2

i hope short and sweet answer help