the square root of 1+ y²+ √1+√y²+y⁴
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Answer:
the answer is very simple
Step-by-step explanation:
The given question =) 1+(y)2+√1+√(y)2+(y)4
we know that √1 = 1 and √(y)2 =y and (y)4=((y)2)2
Answer= 1+(y)2+√1+√(y)2+(y)4
= 1+(y)2+1+y+{(y)2}2 -----Eq(1)
Now apply square root to the eq(1).,
= √1+1+(y)2+y+{(y)2}2
= 1+1+y+√y+(y)2
= 2+y+√y+(y)2
= (y)2+√y+y+2.. is the answer....
Answered by
0
Step-by-step explanation:
1+y^2 + 1 +y + y^4
y^4+y^2+y+2
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