Math, asked by kapoorriya217, 8 months ago

the square root of 1+ y²+ √1+√y²+y⁴​

Answers

Answered by gokulsairayallu
0

Answer:

the answer is very simple

Step-by-step explanation:

The given question =) 1+(y)2+√1+√(y)2+(y)4

we know that √1 = 1 and √(y)2 =y and (y)4=((y)2)2

Answer= 1+(y)2+√1+√(y)2+(y)4

= 1+(y)2+1+y+{(y)2}2 -----Eq(1)

Now apply square root to the eq(1).,

= √1+1+(y)2+y+{(y)2}2

= 1+1+y+√y+(y)2

= 2+y+√y+(y)2

= (y)2+√y+y+2.. is the answer....

Answered by smaheswari1254
0

Step-by-step explanation:

1+y^2 + 1 +y + y^4

y^4+y^2+y+2

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