Math, asked by preethikajodi, 8 months ago

The square root of (2011)5 is

Answers

Answered by AvishkarDarothe
1

Answer:

100

Step-by-step explanation:

Answered by pulakmath007
1

 \sf The  \: square \:  root  \: of \:  \: (2011)_5 = (31)_5

Given :

The number

 \sf (2011)_5

To find :

The square root of the number

Solution :

Step 1 of 3 :

Express in decimal

 \sf (2011)_5

 \sf  = (2 \times  {5}^{3}  + 0  \times  {5}^{2} + 1 \times  {5}^{1}  + 1 \times  {5}^{0} )

 \sf  = 250 + 0 + 5 + 1

 \sf  = 256

Step 2 of 3 :

Find the square root of the number

The square root of 256

 \sf  = \sqrt{256}

 \sf  = 16

Step 3 of 3 :

Express with respect to base 5

The required square root

 \sf  =(16)_{10}

 \sf  =(31)_5

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