Math, asked by laxmirai65, 11 days ago

The square root of a perfect square containing 'n' digits has ...digits.
(1) (n+1)/2
(2) n/2
(3) (n-1) /2
(4) option 1 & 2​

Answers

Answered by itsamy14
0

Answer:

If'n' is even then square root will contain 2n digits.

If 'n' is odd then square root will contain 2n+1 digits.

Step-by-step explanation:

It means 1st opsion

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