the square root of sum of the digit in the square of 121 is
sapnathakral:
11 is the right answer because 11×11=121
yes, is a right answer
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Answered by
9
ꜱqᴜᴀʀᴇ ᴏꜰ 121
(121)²=14641
ᴛʜᴇ ꜱᴜᴍ ᴏꜰ ᴛʜᴇ ᴅɪɢɪᴛꜱ
1+4+6+4+1
=16
ʀᴏᴏᴛ ᴏꜰ 16
=4
ꜱᴏ ᴜ ʀɪɢʜᴛ ᴀɴꜱᴡᴇʀ ɪꜱ 4
(121)²=14641
ᴛʜᴇ ꜱᴜᴍ ᴏꜰ ᴛʜᴇ ᴅɪɢɪᴛꜱ
1+4+6+4+1
=16
ʀᴏᴏᴛ ᴏꜰ 16
=4
ꜱᴏ ᴜ ʀɪɢʜᴛ ᴀɴꜱᴡᴇʀ ɪꜱ 4
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Answered by
1
See it can be done in 2 ways:
121= sum of digits - 1+2+1=4
√4 = 2
As well as:
The square of 121 is:14641
The sum of the digits is: 1+4-6+4+1=. 16
The square root of 16 is 4.
So it depends upon what you think is correct.
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