Question

the square root of sum of the digit in the square of 121 is

Answer 1

$\blue{hey \:mate....\\ square\: root \:of sum \:of\: digits\: in\: square \:of \:121\\ square \:of \:121 = 14641\\ sum\: of \:digits \:of \:14641 = 1+4+6+4+1 = 16\\ square \:root \:of\: 16 \:= \:4\\}$

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