Question

The square root of sum of the digits in the square of 121 is -1)4 2)3 3)6 4)9

Answer 1

hope you will find this helpful

Answer 2

Answer: The correct solution is option 1.

Explanation:

We have to find the square root of sum of the digits in the square of 121.

First we find square of 121.

$(121)^2=121\times 121=14641$

The digits in the square of 121 are 1, 4, 6, 4 and 1. Now add these digits.

$1+4+6+4+1=16$

Now, find the square root of sum of the digits in the square of 121,

$\sqrt{16}=4$

Therefore, the square root of sum of the digits in the square of 121 is 4 and the correct option is 1.