Question

The square root of the sum of digits in the square of 121 is _____???

Options ---

1. 4
2. 3
3. 6
4. 9

Answer 1

$121 {}^{2} = 14641 \\ sum \: of \: digits = 1 + 4 + 6 + 4 + 1 = 16 \\ square \: root = \sqrt{16} = 4$

Answer 2

Answer 1.)4

Square of 121= 14641

Sum of digits of 121²= 1+4+6+4+1=16

Then,

(Square root)√ 16 = 4

So the answer is 4

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