Question

the square root of the the decimal by the converting them into corresponding fraction 2.25​

Answer 1

Step-by-step explanation:

Answer:-

Given that:-

The area of trapezium is 60 cm²

Height of the trapezium is 12 cm

Difference in the length of parallel side 4 cm

To find:-

Parallel sides measures

Let's Do!

Formula to be applied is:-

$\boxed{\sf{ Area \ of \ Trapezium = \dfrac{1}{2} \times (Sum \ of \ Parallel \ sides) \times Height}}$

Area of trapezium and height is given

If we consider the value of one side as x, so other is y.

x - y = 4 is the equation then. (1)

$\boxed{\sf{60 = \dfrac{1}{2} \times (x + y) \times 12}}$

$\sf{120 = (x + y) \times 12}$

$\sf{10 = (x + y) }$ Equation (2)

Adding (1) and (2)

$\sf{x - y + x + y = 4 + 10}$

$\sf{ 2x = 14}$

$\implies \sf{ x = 7 \ cm}$

Now,

$\implies \sf{ x - y= 4}$

$\sf{ 7 - y= 4}$

$\implies \sf{ y= 3 \ cm}$

Answer 2

Step-by-step explanation:

Answer:-

Given that:-

The area of trapezium is 60 cm²

Height of the trapezium is 12 cm

Difference in the length of parallel side 4 cm

To find:-

Parallel sides measures

Let's Do!

Formula to be applied is:-

$\boxed{\sf{ Area \ of \ Trapezium = \dfrac{1}{2} \times (Sum \ of \ Parallel \ sides) \times Height}}$

Area of trapezium and height is given

If we consider the value of one side as x, so other is y.

x - y = 4 is the equation then. (1)

$\boxed{\sf{60 = \dfrac{1}{2} \times (x + y) \times 12}}$

$\sf{120 = (x + y) \times 12}$

$\sf{10 = (x + y) }$ Equation (2)

Adding (1) and (2)

$\sf{x - y + x + y = 4 + 10}$

$\sf{ 2x = 14}$

$\implies \sf{ x = 7 \ cm}$

Now,

$\implies \sf{ x - y= 4}$

$\sf{ 7 - y= 4}$

$\implies \sf{ y= 3 \ cm}$