Question

The square root of x4+ 10x3+ 27x2 + 10x + 1 is x2 + kx + 1 then k =​

Answer 1

Answer:

5

Step-by-step explanation:

root of x4+ 10x3+ 27x2 + 10x + 1 = x2 + kx + 1

squaring on both sides

x4+ 10x3+ 27x2 + 10x + 1 = (x2 + kx + 1)^2

=(x2)^2+(kx)^2+1^2+2*x^2*kx+2*kx*1+2*1*x^2

= x^4+k^2x^2+1+2kx^3+2kx+2x^2

= x^4+2kx^3+(2+k^2)x^2+2kx+1

comparing the coefficient of x on both sides

10=2k

k=5

Answer 2

Answer:

5

Step-by-step explanation: