The squareplot has a fence 240 cm. If the tiles are to be fixed in the plot, how many tiles have tobe bought when a tile size is 9 cm long and 4 cm breadth?
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Answer:
100 Tiles had to be bought to fix on the plot.
Step-by-step explanation:
Given :
Length of fence of square plot = 240 cm.
AS we know that ,
Length pf fence of square plot = perimeter of square = 240 cm.
Perimeter of square = 4 × length of one side
∴ length of one side = perimeter / 4
= 240 / 4 = 60 cm.
Area of square = side × side
= 60 × 60 = 3600 sq. cm.
Length of 1 tile = 9 cm.
Breadth of 1 tile = 4 cm.
Area of 1 tile = length × breadth = 9×4 =36 sq.cm.
Number of tiles are to be fixed in the plot = area of plot / area of 1 tile
= 3600 / 36 = 100
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