The squares of two consecutive positive integers differ by 2003. What is the sum of these two integers?
Answers
Answered by
0
Answer:
2003
Step-by-step explanation:
Let the integers be x and x + 1.
Given (x+1)
2
−x
2
=2003. According to the given condition,
x
2
+2x+1−x
2
=2003
2x+1=2003
x+(x+1)=2003
∴ Required sum =2003.
Answered by
0
Answer:
Required sum =2003.
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