Math, asked by adityakumar1975in, 6 months ago

The squares of two consecutive positive integers differ by 2003. What is the sum of these two integers?

Answers

Answered by adityagupta3011
0

Answer:

2003

Step-by-step explanation:

Let the integers be x and x + 1.

Given (x+1)

2

−x

2

=2003. According to the given condition,

x

2

+2x+1−x

2

=2003

2x+1=2003

x+(x+1)=2003

∴ Required sum =2003.

Answered by paarthvashistha
0

Answer:

Required sum =2003.

Mark as brainliest

Similar questions