Question

The squares of two positive integers differ by 2016. Find their maximum
possible sum.

Answer 1

Answer:add 2016+2016 the ansewr will be 4032

Easy as That.

Hope it helps!

Answer 2

Answer: 2016

Step-by-step explanation:

let, the two number 'x' and 'y'.

So, we can say that,
x^2 - y^2 = 2016 (x>y)

By simplifying this,
(x+y)(x-y) = 2016

From this, we can say that the value of (x+y) can be 2016 at most.

So the answer will be 2016.