Question

The stability order of alkyl free radicals is?

a) tert.˂sec.˂pri.˂CH3 b) tert.˂pri.˂sec.˂CH3

c) tert. ˃ sec. ˃ pri. ˃ CH3 d) sec. ˃ tert. ˃ pri. ˃ CH3​

Answer 1

$\bf \large\underline{Answer: }$

• The correct order of stability of alkyl free radicals is tert. > sec. > pri. > CH₃ , because we know that alkyl free radicals are e⁻ deficient and it requires e⁻ to attain stability.

So, In 3° alkyl free radicals it get donation from 3 sides so it gains more stability. (+I effect)

And ,In 2° alkyl free radicals it get donation from 2 side so it gains less stability as compared to 3°

CH₃

And In 1° alkyl free radicals it gets donation from only 1 side so it gains less stability as compared to 3° & 2°

CH₃-CH₂•

And In methyl carbon free radicals it doesn't gain donation from any side so it's least stable.

CH₃•

• Therefore, Option C is correct.

Answer 2

Explanation:

Option c is correct!!!!!