Question

the stable nucleus tha has a radius 1\3 that of Os(189) is a.li(7) b.he(4). c.B(10). d.C(12)

Answer 1

• Answer:
• Answer:Correct option is
• Answer:Correct option isA
• Answer:Correct option isA3Li7
• Answer:Correct option isA3Li7We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then
• Answer:Correct option isA3Li7We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then R1R0=(A1189)1/3
• Answer:Correct option isA3Li7We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then R1R0=(A1189)1/3Given that R1=R0/3 so we get 33=A1189
• Answer:Correct option isA3Li7We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then R1R0=(A1189)1/3Given that R1=R0/3 so we get 33=A1189So A1=27189=7
• Answer:Correct option isA3Li7We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then R1R0=(A1189)1/3Given that R1=R0/3 so we get 33=A1189So A1=27189=7Option A is correct.

Explanation:

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Answer 2

Answer:

Correct option is

A)3Li7

Explanation:

We know that radius R=1.2×10−15A1/3m, where A is mass number which is 189 for Os, suppose it is A1 for stable nuclei then

R1R0=(A1189)1/3

Given that R1=R0/3 so we get 33=A1189

So A1=27189=7

Option A is correct.