The standard electrode potential e i2/i- , e br-/br2
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This reaction is not feasible because the value of electrode potential is negative. i.e. Eocell = -0.55 V
Explanation:
If the standard electrode potential of the cell or Eocell of the reaction is positive, then the reaction is spontaneous and feasible.
Oxidation half: 2Br− → Br2 + 2e− EO = −1.09 V
Reduction half: I2 + 2e− → 2I− EO = 0.54 V
So, Eocell = -0.55 V
Thus this reaction is not feasible because the value of electrode potential is negative. i.e. Eocell = -0.55 V
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What is electrode and electrode potential ?
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