The standard electrode potential (E°) for Daniel cell is +1.1 V. Calculate the â³G° for the reaction.
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we have Zn(s) + Cu2+(aq)------- Zn2+(aq) + Cu(s)
gibbs free enrgy =-n FE
where n is the number of electron=2
F is the faradays constant,here it is 96500C
E is the EMF of the cell =1.1V
Gibbs free energy=-2*96500*1.1 J
= -212.3 KJ
gibbs free enrgy =-n FE
where n is the number of electron=2
F is the faradays constant,here it is 96500C
E is the EMF of the cell =1.1V
Gibbs free energy=-2*96500*1.1 J
= -212.3 KJ
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