Question

The standard electrode potential for Daniell cell is 1.1V. Calculate
the standard Gibbs energy for the reaction:
Zn(s) + Cu(aq) Zn (aq) + Cu(s)??​

Answer 1

Answer:

Refer to attachment please

Explanation:

....

Answer 2

Explanation:

•we have Zn(s) + Cu2+(aq)------- Zn2+(aq) + Cu(s)

•gibbs free enrgy =-n FE

[where n is the number of electron=2]

•F is the faradays constant,here it is 96500C

•E is the EMF of the cell =1.1V

•Gibbs free energy=-2*96500*1.1 J

= -212.3 KJ

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