The standard electrode potential of the half cells
are given below
Zn²⁺ + 2e⁻ ⟶ Zn ; E = – 7.62 V
Fe²⁺ + 2e⁻ ⟶ Fe ; E = – 7.81 V
The emf of the cell, Fe²⁺+Zn ⟶ Zn²⁺ + Fe is
(a) 1.54 V (b) – 1.54 V
(c) – 0.19 V (d) +0.19 V
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Answer:
c. will be correct answer
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