The standard emf of a galvanic cell involving cell reaction with n=2 found to be 0.295 at 298 k the equilibrium constant will be
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Answer : The value of at 298 is,
Solution :
First we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.295 V
Now put all the given values in this formula, we get the Gibbs free energy.
Now we have to calculate the value of equilibrium constant.
Formula used :
where,
R = universal gas constant = 8.314 J/K/mole
T = temperature = 298 K
= equilibrium constant = ?
Now put all the given values in this formula, we get the value of
Therefore, the value of at 298 is,.....
Solution :
First we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.295 V
Now put all the given values in this formula, we get the Gibbs free energy.
Now we have to calculate the value of equilibrium constant.
Formula used :
where,
R = universal gas constant = 8.314 J/K/mole
T = temperature = 298 K
= equilibrium constant = ?
Now put all the given values in this formula, we get the value of
Therefore, the value of at 298 is,.....
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