Question

The standard EMF of Danielle cell is 1.10 volt.The maximum electrical work obtained from the Daniell cell is

Answer 1

Delta Go = nF Eo

where n is the number of electrons in redox reaction of Daniel.cell, which is 2
F = 96500 C/mol
Eo = 1.1 V

thus,
Delta Go = 2*96500*1.1 = 212300J

Answer 2

Explanation:

Gibb's free energy is the maximum amount of work done by a system.

Relation between $\Delta G$ and $E_{o}$ is as follows.

           $\Delta G = n \times F \times E_{o}$

where,        $\Delta G$ = Gibb's free energy

                      n = number of electrons participating in the redox reaction of Daniel cell

                      F = Faraday's constant = 96500 C/mol

                      $E_{o}$ = EMF of the cell

Therefore, in a Daniel cell number of electrons involved in the redox reaction are 2.

Hence, putting the values into the above formula as follows.

                     $\Delta G = n \times F \times E_{o}$

                                   = $2 \times 96500 C/mol \times 1.10 volt$

                                   = 212300 J                    

Thus, we can conclude that maximum electrical work obtained from the Daniell cell is 212300 J.