Question

The standard form of 5/(-15) is

Answer 1

Step-by-step explanation:

The standard form of

$\frac{5}{ - 15} = \frac{ - 1}{3}$

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

The standard form of $\frac{5}{(-15)}$ is ?

$\huge\bold{\mathtt{To\:find⇒}}$

The standard form.

$\huge\bold{\mathtt{Solution⇒}}$

A rational number is said to be in standard form if its numerator and denominator are integers having no common divisor other than 1 and the denominator is positive.

Here, we can see that:

• Both 5 and (-15) are divisible by 5.

• The denominator (-15) is negative.

So,

We have to divide both the numerator and denominator by 5.

$\frac{5}{(-15)}$

= $\frac{(5÷5)}{([-15)÷5]}$

= $\frac{1}{(-3)}$

Since the denominator is negative, we have to make it positive.

$\frac{1}{(-3)}$

= ${\frac{(-1)}{3}}\:\:\:{\large\red{★}}$

$\huge\bold{\mathtt{Hence⇒}}$

$\frac{5}{(-15)}$ in standard form is $\frac{(-1)}{3}.$

$\huge\bold{\mathtt{Done࿐}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

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