Question

The standard form of a linear equation in one variable x is

opsen is
1. ax+b=0
2. ax²+bx+c=0
3. ax³+bx²+cx+d =0
4. none of these
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Answer 1

Answer

1.ax+b=0

hope it helps you

Answer 2

Answer:

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Step-by-step explanation:

If the equation ax³ + bx² + cx + d=0 has roots −1, −3, and 5, then what are the three factors of this equations?

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If we divide a polynomial P(x) by another polynomial D(x) then we can find quotient Q(x) and remainder R(x) such that degree of R(x) is less than degree of divisor D(x) and P(x)=D(x)Q(x)+R(x).

Now, if we can find D(x) such that when D(x)=0, P(x) become 0 then the relationship shown above becomes 0=0 × Q(x)+R(x)=> 0=0+R(x)=>0=R(x).

Putting this in original relationship, we get P(x)=D(x)Q(x).

So, if D(x)=0=>P(x)=0 then D(x) is a factor of P(x).

It is given that P(x)=0 when x=-1; in other words P(x)=0 when (x+1)=0. Hence (x+1) is a factor.

Similarly, (x+3) and (x-5) are factors.

Ans.: (x+1), (x+3) and (x-5).

p.s.: Factorization is a(x+1)(x+3)(x-5)

Multiplying all 3 (except a), we get

Verification:

For x=-1, a(-1–1+17–15)=a x 0=0

For x=-3, a(-27–9+51–15)=a × 0=0

For x=5, a(125–25-85–15)=125 × 0=0

Thank you