The standard free change for reduction of one mole of Feo is
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1
Answer:
ANSWER
Fe+
2
1
O
2
⟶FeO;ΔH=−65kcalmol
−1
. ..(i)
2Fe+
2
3
O
2
⟶Fe
2
O
3
;ΔH=−197kcalmol
−1
...(ii)
By eq, [(ii)−2×(i)]
Also, 2FeO+
2
1
O
2
⟶Fe
2
O
3
;ΔH=−67kcalmol
−1
...(iii)
Let a mole of FeO and b mole of Fe
2
O
3
, are present such that
a+b=1and
b
a
=2
a=
3
2
andb=
3
1
2FeO+
2
1
O
2
⟶Fe
2
O
3
Initial a b
After oxidation (a−2a
′
) b+a
′
Given,
b
a
=2and
b+a
′
a−2a
′
=
2
1
∴
2
a
+a
′
a−2a
′
=
2
1
∴2a−4a
′
=
2
a
+a
′
∴a
′
=
10
3a
=
10×3
3×2
=
5
1
∴FeOused=2a
′
=2/5mol
∵2moleFeOgives67kcal.
∴
5
2
moleFeOgives
2×5
67×2
=13.4kcalheat.
Answer =
6
13.4
≈2
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