Question

The standard heat of
combustion of ethanol,
C2H5OH. is 1372 kJ/mol
ethanol. How much heat
(in kJ) would be liberated
by completely burning a
20.0 g sample?
Select one:
a. 715 kJ
b. 686 kJ
c. 519 kJ
d. 597 k]​

Answer 1

Explanation:

please answer this question

Answer 2

Answer:

597kj

Explanation:

weight of C2H50H is 46 gm

1372 kj/mole required for 46 gm then for 20 hm

20/46×1372 =597kj