The standard heat of combustion of graphite carbon is -393.5 KJ mol-1. The standard enthalpy of CO 2is
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Answer:
At 300K, the standard enthalpies of formation of C6H5COOH(s),CO2(g), and H2O(l) are -408, -393 and -286 kJ mol respectively.
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Given standard enthalpy of formation of CO (-110 KJ mol
−1) and CO 2
(-394 KJ mol −1 ). The heat of combustion when one mole of graphite burns is:
ANSWER
Enthalpy of formation of CO=−110kJ/mol
Enthalpy of formtaion of CO 2
=−394kJ/mol
C+O2
→CO 2
△H c
= −394kJ/mol
Formation of Carbon monoxide
C+ 21 O 2
= CO ∆H c'
=−110kJ/mol
ΔH=ΔHc
−ΔH c′
=−394−(−110)
=−394+110
=−284kJ/mol
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