Chemistry, asked by raghuvirda, 6 months ago

The standard heat of combustion of graphite carbon is -393.5 KJ mol-1. The standard enthalpy of CO 2is

Answers

Answered by arjunsing1104
3

Answer:

At 300K, the standard enthalpies of formation of C6H5COOH(s),CO2(g), and H2O(l) are -408, -393 and -286 kJ mol respectively.

Explanation:

mark brainliest and follow

Answered by mahaksanyal964
3

Given standard enthalpy of formation of CO (-110 KJ mol

−1) and CO 2

(-394 KJ mol −1 ). The heat of combustion when one mole of graphite burns is:

ANSWER

Enthalpy of formation of CO=−110kJ/mol

Enthalpy of formtaion of CO 2

=−394kJ/mol

C+O2

→CO 2

△H c

= −394kJ/mol

Formation of Carbon monoxide

C+ 21 O 2

= CO ∆H c'

=−110kJ/mol

ΔH=ΔHc

−ΔH c′

=−394−(−110)

=−394+110

=−284kJ/mol

Similar questions