Question

The standard heat of forination of sodium ions in aqueous solution from the following data:
Heat of formation of NaOH) at 25°C = - 470.7KJ:
Heat of formation of OH at 25°C = -228.8KJ is :
1)-251.9KJ
2) 241.9KJ
3) -241.9KJ
4) 300KJmol-1​

Answer 1

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Answer 2

Hence the required answer is -241. 9\KJ

Explanation:

Given:-

${\Delta{{H}_{f}}}_{NaOH} = - 470.7 \ KJ$

$\Delta H _f_o_h = -228.8 \ KJ$

$\Delta H_f_H^+ = ?$

$Naoh \rightarrow Na^+ + OH^ {-1}$

$\Delta h_f_N_a_o_h = \Delta H_f_o_H^{-1} + \Delta H_f_H^+$

$-4707 = - 228.8 + \Delta H_f_H^+$

$\Delta H_f_H^+ = -470.7 + 228.82$

                            $= -241.9\ KJ$

Hence the required answer is -241.9 KJ