The standard heats of formation of CO(g) and H2O(g) at 25°C are 100.5 kJ and –241.8 kJ per mole
respectively. Calculate the heat change of the following reaction at this temperature.
H2O(g) + C(s) → H2(g) + CO(g)
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Answer:
△H=H
f
∘
(products)−H
f
∘
(reactants)
Reactants are: CO
2
H
2
and products are CO and H
2
O
Hence,
ΔH =−100.5+(−241.8)−(−393.5+0)=41.2 kJ
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