Question

The standard reduction potential eo for half reaction are zn zn2+ + 2e- eo = 0.76 v fe fe2+ + 2e- eo = 0.41 v the emf of the cell reaction fe2+ + zn zn2+ + fe is

Answer 1

Answer:

EMF = E°(cathode) - E°(anode)

= 0.76 - 0.41 V.

= 0.35 V

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