The star of a distant solar system explodes as a supernova. At the moment of the explosion, a resting exploration spaceship is 15 AU away from the shock wave. The shock wave of the explosion travels with 25000 km/s towards the spaceship. To save the crew, the space rah makes use of a special booster that uniformly accelerates at 150 m/s2 in the opposite direction.
Determine if the crew manages to escape from the shock wave. (Neglect relativistic eVects.)
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Answer:
First of all Calculate the time it takes for the spaceship to reach 25000 km/s:
we know,
t=v/a
=166667 s.
Then, Calculate what distance the shockwave will cover during t:
d=v . t
=4.167·10^12m,
or 27.85 AU.
So, only 27.85-15=12.85 AU left for the spaceship to develop the speed of 25000 km/s. Is it possible? Find the distance required for the ship to accelerate from rest to 25 000 000 m/s with acceleration of 150 m/s2:
d=v^2/2a
=2.08·10^12m
or 13.9 AU.
Therefore, when the shockwave will travel 27.85 AU from the star at 25 000 km/s, the speed of the spaceship will be lower than 25 000 km/s. They cannot escape.
Explanation:
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